# Chem

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Calculate the number of grams of Fe formed when 0.300kg of Fe2O3 reacts.
Equation:
Fe2O3+CO-->Fe+CO2

converted .300kg to 300g
Balanced Fe2O3+3CO-->2Fe+3CO2

So I started by trying this:
300gFe2O3(1molFe2O3/159.687gFe2O3)...and then I don't know where I would go from there. I'm not even sure if I'm even starting off right. I'm trying to follow along with the teacher's notes, but she didn't have anthing like this.

• Chem - ,

how many moles of Fe2O3 do you have? figure that.
Then, the balanced equation tells you that you get twice that number of moles of Fe.

300gFe2O3(1molFe2O3/159.687gFe2O3)*2moleFe/1moleFe2O3

• Chem - ,

Yeah, I balanced it already; I put it up. My teacher didn't do this, that's why I didn't know how to start, but is that pretty much all I have to do? That extra multiplication/division?

• Chem - ,

Just to clarify, when I convert from moles to grams, do I double Fe because it has the coefficient 2?

• Chem - ,

I got the answer (210grams). Thanks.