find the value of each variable (6y-16)
(4y+6)
Did you even look at the solution I gave you earlier to the same kind of question ?
http://www.jiskha.com/display.cgi?id=1347840805
(x+20)(x+10)(y-40)
To find the value of each variable in the expressions (6y - 16) and (4y + 6), we need to equate them to zero and solve for y individually.
For the first expression (6y - 16):
6y - 16 = 0
To isolate y, we can add 16 to both sides of the equation:
6y = 16
Then, divide both sides of the equation by 6 to solve for y:
y = 16/6
Simplifying further, we get:
y = 8/3 or approximately 2.67
Therefore, in the expression (6y - 16), the value of the variable y is 8/3 or approximately 2.67.
Now let's move on to the second expression (4y + 6):
4y + 6 = 0
To isolate y, we can subtract 6 from both sides of the equation:
4y = -6
Then, divide both sides of the equation by 4 to solve for y:
y = -6/4
Simplifying further, we get:
y = -3/2 or -1.5
Therefore, in the expression (4y + 6), the value of the variable y is -3/2 or -1.5.