what is the final temperature of aluminum when 26.4 cal of heat is added to 18.1 g of aluminum at 21.0 degrees c
q = mass Al x specific heat Al x (Tfinal-Tinitial)
To determine the final temperature of aluminum, we need to use the formula:
q = m * c * ΔT
where:
- q is the heat absorbed or released by the substance (in this case, aluminum)
- m is the mass of the substance (in grams)
- c is the specific heat capacity of the substance (in calories/gram °C)
- ΔT is the change in temperature (in °C)
To solve for the final temperature, we rearrange the formula as follows:
ΔT = q / (m * c)
Now let's substitute the given values into the equation:
- q = 26.4 cal (heat added)
- m = 18.1 g (mass of aluminum)
- c = specific heat capacity of aluminum, which is 0.21 cal/g °C (approximately)
Therefore, the equation becomes:
ΔT = 26.4 cal / (18.1 g * 0.21 cal/g °C)
Now, let's calculate:
ΔT = 26.4 cal / (3.801 g °C)
ΔT ≈ 6.93 °C
To find the final temperature, we add the change in temperature (ΔT) to the initial temperature:
Final temperature = Initial temperature + ΔT
Since the initial temperature is 21.0 °C, the final temperature of aluminum will be:
Final temperature ≈ 21.0 °C + 6.93 °C
Final temperature ≈ 27.93 °C
Therefore, the final temperature of aluminum will be approximately 27.93 °C.