Post a New Question


posted by .

Octane has a density of 0.692 at 20degree C . How many grams of O2 are required to burn 17.0gal of C8H18 ?

Step-by-step explanation much appreciated with as much detail as possible so I can understand. Thanks!

  • Chemistry -

    0.692 what? g/mL?

    2C8H18 + 25O2 ==> 16CO2 + 18H2O

    Convert 17.0 gallons octane to L, then to mL.
    Use density (in g/mL?) to convert mL octane to grams octane.
    Convert grams octane to mols. mols = grams/molar mass
    Use the coefficients in the balanced equation to convert mols octane to mols O2.
    Now convert mols O2 to grams. g = mols x molar mass.

  • Chemistry -


  • Chemistry -


Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question