A stone is dropped from the top of a well. If the well is 23.1 meters deep, how long with the stone take to reach the bottom?
h=gt solve for time t.
A stone is dropped from the top of a well that has water in it at a depth of 65.0 m. How long does it take the stone to reach the water?
To determine how long it will take for the stone to reach the bottom of the well, we can use a formula from classical physics. The formula is based on the principles of acceleration due to gravity. The formula to calculate the time it takes for an object to fall freely is:
t = sqrt((2d) / g)
where:
t represents time (in seconds)
d represents the depth of the well (in meters)
g represents the acceleration due to gravity (approximately 9.8 m/s²)
Let's substitute the values into the formula to find the time it takes for the stone to reach the bottom:
t = sqrt((2 * 23.1) / 9.8)
t = sqrt(46.2 / 9.8)
t = sqrt(4.71428571429)
t ≈ 2.17 seconds
Therefore, it will take approximately 2.17 seconds for the stone to reach the bottom of the well when dropped from the top.