Posted by shaun on Sunday, September 16, 2012 at 10:30am.
(sum of 3 consecutive primes )^2 = 72361
sum of 3 consecutive primes = 269
269/3 = 89
so the middle prime must be around 89
BUT 89 is a prime
http://primes.utm.edu/lists/small/10000.txt
the one before is 83 and the one after is 97
So the largest of these primes is 97
check:
(83+89+97)^
= 269^2
= 72361 , YEAH!
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