a rectangle has length of 28cm and weadth of 12cm.what is the area of the least number of these rectangles used to form te smallest square possible
To find the area of the smallest square formed by the least number of these rectangles, you need to find the greatest common divisor (GCD) of the length and width of the rectangle.
In this case, the length is 28 cm and the width is 12 cm. The GCD of 28 and 12 is 4.
To form the smallest square, you need to arrange the rectangles in such a way that the length and width of the square are both divisible by the GCD. In this case, the length and width of the smallest square would be 28 cm / 4 = 7 cm, and 12 cm / 4 = 3 cm, respectively.
Therefore, the area of the smallest square is 7 cm * 7 cm = 49 cm^2.