The area of field in the shape of trapezium is 217msq. If its altitude is 14m nd the length of one of its bases is 18m,find the length of its other base.
Gve me ful sltn plz nd ans is13m
A = 0.5(B1+B2)h. = 217m^2.
0.5(18+B2)14 = 217
126 + 7B2 = 217
7B2 = 217 - 126 = 91
B2 = 13 m^2.
To find the length of the other base of the trapezium, we can use the formula for the area of a trapezium, which is given by:
Area = (1/2) * (sum of the bases) * altitude
We are given that the area is 217 square meters, the altitude is 14 meters, and one of the bases is 18 meters. Let's denote the length of the other base as x.
Plugging in the given values into the formula, we have:
217 = (1/2) * (18 + x) * 14
Let's solve for x:
Multiply both sides of the equation by 2 to remove the fraction:
2 * 217 = (18 + x) * 14
434 = 14 * (18 + x)
Divide both sides of the equation by 14 to isolate the expression (18 + x):
434 / 14 = 18 + x
31 = 18 + x
Subtract 18 from both sides of the equation:
31 - 18 = x
13 = x
Therefore, the length of the other base of the trapezium is 13 meters.
To solve this problem, we can use the formula for the area of a trapezium:
Area = (altitude * (sum of bases)) / 2
Given:
Area = 217 m²
Altitude = 14 m
Length of one base = 18 m
Let's substitute these values into the formula and solve for the other base:
217 = (14 * (18 + other base)) / 2
Multiply both sides of the equation by 2 to eliminate the fraction:
434 = 14 * (18 + other base)
Divide both sides by 14:
31 = 18 + other base
Now, isolate the other base by subtracting 18 from both sides:
other base = 31 - 18
other base = 13
Therefore, the length of the other base is 13 meters (as mentioned in the question).