Posted by tom on Saturday, September 15, 2012 at 12:11am.
What do you mean by displacement? Horizontal distance from the edge, or the actual slant distance (the resultant of vertical and horizontal components) from the edge?
I will assume the latter, since you refer to the magnitude.
In 0.58 s, the car will fall
Y = (g/2)*t^2 = 1.648 meters
The horizontal distance it will have moved is then
X = sqrt[(7.1)^2 - (1.648)^2] = 6.91 m
The car's speed at the edge would be
X/t = 6.91/0.58 = 11.9 m/s
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