The barrel of a rifle has a length of 0.916m. A bullet leaves the muzzle of a rifle with a speed of 621m/s.

What is the acceleration of the bullet while in the barrel? A bullet in a rifle barrel does not have a constant acceleration, but constant acceleration is to be assumed for this problem.
Answer in unites of m/s^2.

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To find the acceleration of the bullet while in the barrel, we can use the kinematic equation:

v^2 = u^2 + 2as

Where:
v = final velocity (621 m/s)
u = initial velocity (unknown)
a = acceleration (unknown)
s = displacement or distance traveled (0.916 m)

We are looking for the acceleration, so we rearrange the equation to solve for a:

a = (v^2 - u^2) / (2s)

Substituting the given values:

a = (621^2 - u^2) / (2 * 0.916)

Since the bullet starts from rest (u = 0), we can simplify the equation:

a = (621^2) / (2 * 0.916)

Now we can calculate the acceleration:

a = 621^2 / 1.832

a ≈ 249,039 / 1.832

a ≈ 136,001.6 m/s^2

Therefore, the acceleration of the bullet while in the barrel is approximately 136,001.6 m/s^2.