A tennis ball with a speed of 14m/s is moving perpendicular to a wall. After striking the wall, the ball rebounds in the opposite direction with a speed of 11.41m/s. If the ball is in contact with the wall for 0.0112s, what is the average acceleration of the ball while it is in contact with the wall? Take "toward the wall" to be the positive direction.
Answer in unite of m/s^2
To find the average acceleration of the tennis ball while it is in contact with the wall, we can use the formula:
Average acceleration = Change in velocity / Time taken
First, let's find the change in velocity. The ball initially moves with a speed of 14 m/s towards the wall. After striking the wall, it rebounds with a speed of 11.41 m/s in the opposite direction. The change in velocity is therefore the difference between these two speeds:
Change in velocity = final velocity - initial velocity
= 11.41 m/s - (-14 m/s)
= 11.41 m/s + 14 m/s
= 25.41 m/s
Next, we need to determine the time taken for the ball to be in contact with the wall. Given that the ball is in contact with the wall for 0.0112 seconds, we can use this value as the time.
Now let's substitute the values into the formula:
Average acceleration = Change in velocity / Time taken
= 25.41 m/s / 0.0112 s
≈ 2269.64 m/s^2
Therefore, the average acceleration of the ball while it is in contact with the wall is approximately 2269.64 m/s^2.