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September 30, 2014

September 30, 2014

Posted by **Taylor** on Friday, September 14, 2012 at 6:31pm.

- Math -
**Reiny**, Friday, September 14, 2012 at 8:28pmOne way to look at it is to consider one of the trains to be standing still, and the second moving at (60+70) mph or 130 mph.

So from the point when the moving train meets the front of the stationary train to when its end reaches the end of the stationary train is 230+220 ft or 450 ft.

450 ft = 450/5280 miles = .085227.. miles

time = .085227../130

= .000655594 hours

= .03933 minutes

= 2.36 seconds

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