Physics
posted by Ellise on .
A diver running 1.1 m/s dives out horizontally from the edge of a vertical cliff and 3.3 s later reaches the water below.
How high was the cliff?
How far from its base did the diver hit the water?

Cliff height = (g/2)*t^2
(how far it falls in 3.3 s)
g is the acceleration of gravity and t = 3.3 s in this case.
Horizontal displacement = 1.1 m/s*3.3 s = 3.63 m