a ball is thrown upward what is its maximun height? its initial vertical speed is 8.1 m/s and the acceleration of gravity is 9.8 m/s . neglet air resistance . answer in units of m
h=v²/2g
12.6
To find the maximum height reached by the ball, we can use the following equation:
h = (v^2 - u^2) / (2g)
where:
h = maximum height
v = final vertical velocity (at maximum height, the ball's velocity is zero)
u = initial vertical velocity
g = acceleration due to gravity
In this case, the initial vertical velocity (u) is 8.1 m/s and the acceleration due to gravity (g) is 9.8 m/s^2. Since the ball is thrown upward, the final vertical velocity (v) will be zero at the maximum height.
Plugging in the values into the equation, we get:
h = (0 - (8.1)^2) / (2 * 9.8)
Simplifying:
h = (-65.61) / 19.6
h ≈ -3.35 m
Since the height cannot be negative, the maximum height attained by the ball is approximately 3.35 meters.