Calculus (Check)
posted by Greg on .
This seems to easy. Check please.
Find.
Lim (x^2)4
x>2 e
I substitute in 2
(2^2)4
e
gives me
44
e
So my answer is e^0 or 1.

from the work that you show , I must assume you have
Lim e^(x^2  4) as x> 2
= e^0 = 1
you are correct