I'm stumped on this one.
Calculus with Analytical geometry - Steve, Friday, September 14, 2012 at 2:30pm
as written, there's no problem. Just plug in 1 to get
|1-1| (sin 1/1-1) = 0.
However, I think you mean
again, no problem. Since sin is always less than 1, we have 0 * z, where z<1, so zero again.