Posted by **Greg** on Friday, September 14, 2012 at 12:22pm.

I'm stumped on this one.

lim |x-1|sin(1/x-1)

x->1

- Calculus with Analytical geometry -
**Steve**, Friday, September 14, 2012 at 2:30pm
as written, there's no problem. Just plug in 1 to get

|1-1| (sin 1/1-1) = 0.

However, I think you mean

|x-1|sin(1/(x-1))

again, no problem. Since sin is always less than 1, we have 0 * z, where z<1, so zero again.

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