Calculus with Analytical geometry
posted by Greg on .
I'm stumped on this one.
lim x1sin(1/x1)
x>1

as written, there's no problem. Just plug in 1 to get
11 (sin 1/11) = 0.
However, I think you mean
x1sin(1/(x1))
again, no problem. Since sin is always less than 1, we have 0 * z, where z<1, so zero again.