Posted by Jane on Friday, September 14, 2012 at 10:48am.
since BD bisects <ABC, m<ABD = m<DBC
4x-16 = 2x+6
2x = 22
x = 11
m<ABC = m<ABD + m<DBC = 4*11-16 + 2*11+6 = 28+28 = 56
Steve, thank you so much. You explained it so I could understand it.
That's the plan. :-)
in triangle ABC, BD bisects <ABC, <ABD = 4x + 6 and m<DBC = 5x -5. find the m<abc
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