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October 25, 2014

October 25, 2014

Posted by **Hannah** on Friday, September 14, 2012 at 12:35am.

- Algebra 2 (Math) -
**Steve**, Friday, September 14, 2012 at 11:01amthere are several ways to attack this problem. One is to get the equation of the line perpendicular to AB which passes through C. If the intersection is at P, the the altitude is CP

line through A,B

(y+17) /x = (12/4) = 3

y = 3x - 17

slope of that line is 3, so slope of ┴ is -1/3

line through C with slope -1/3 is

(y+1) = -1/3 (x-12)

y = -1/3 x + 3

The lines intersect at (6,1)

length of CP = √(6^2 + 2^2) = 2√10

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