Posted by Emily on Thursday, September 13, 2012 at 7:40pm.
Find all the values of x in the interval [0,2π] that satisfy the equation: 8sin(2x)=8cos(x)

math  Anonymous, Thursday, September 13, 2012 at 7:42pm
3 1/2+ 3/4 = xz\

math  Anonymous, Thursday, September 13, 2012 at 7:48pm
^ that's not the answer

math  Reiny, Thursday, September 13, 2012 at 7:49pm
8sin(2x)=8cos(x)
8(2sinxcosx)  8cosx = 0
16sinxcosx  8cosx = 0
8cosx(2sinx  1) = 0
cosx = 0 or sinx = 1/2
if cosx = 0, x = π/2 or x = 3π/2
if sinx = 1/2, x = π/6 or 5π/6
x = 0, π/6, 5π/6, 3π/2

math  Anonymous, Thursday, September 13, 2012 at 8:07pm
I think you mean x = π/2, π/6, 5π/6, 3π/2... 0 shouldnt be included

you are correct  math  Reiny, Thursday, September 13, 2012 at 8:14pm
good catch anonymous.
that was just a typo, notice I actually had the right answer in the solution part.
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