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December 27, 2014

December 27, 2014

Posted by **Drew** on Thursday, September 13, 2012 at 2:37pm.

(a) Where is the ball after 2.00 s for the horizontal and vertical position?

(b) If the ball is still in the air, how long before it hits the ground?

If the ball is still in the air, where will it be with respect to the starting point once it lands?

- Physics -
**Scott**, Thursday, September 13, 2012 at 6:33pma) vertical __ H = (-.5 * g * 2.00^2) + 20.60 __ g is gravitational acceleration

horizontal __ d = 19.0 * 2.00

b) H = 0 when the ball hits the ground

0 = (-.5 * g * t^2) + 20.60

solve for t to find the flight time

- Physics -
**Jerry**, Thursday, September 13, 2012 at 6:42pmWith your equation, my vertical and horizontal answers are correct, however the equation for T is wrong. Any other suggestions?

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