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December 18, 2014

December 18, 2014

Posted by **Angel** on Thursday, September 13, 2012 at 1:40pm.

Given:

Average Velocity = 1 m/s

Water per day = 6,000 m^3/day

Want to find the diameter of fluid flow.

I am using the eqation:

D = sqrt(4*q)/(pi*v)

q= volumetric flow rate (6,000 m^3/day)

v= velocity (1 m/s)

when I solve I get 87.4 m^2/s*day. How do i change it do just cm?

- Math & Chemistry -hmmm -
**Steve**, Thursday, September 13, 2012 at 3:48pmI think there's a problem here

sqrt(4q) is sqrt(m^3/day)

v = m/s = sqrt(m^2/s^2)

so, D is sqrt(m^3/day * s^2/m^2) = sqrt(m-s^2/day)

sec^2/day will resolve to just sec, so

D is sqrt(m-s)

If you want just meters, you have a problem. YOu need to multiply by sqrt(m/s)

Sure that it's not

D = sqrt(4q)/(pi*v)^(3/2)

?

- Math & Chemistry -
**Anonymous**, Thursday, September 13, 2012 at 4:09pmI'm not sure how to solve this problem actually. My instructor just said flow area * velocity = volumetric flow rate. Find the diameter.

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