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August 30, 2014

August 30, 2014

Posted by **Sherry** on Thursday, September 13, 2012 at 11:53am.

(a) Find the maximum height of the ball above the ground.

(b) Calculate the speed of the ball at the highest point in the trajectory.

- Physics -
**Scott**, Thursday, September 13, 2012 at 2:02pmthe vertical component of the velocity (Vv)is __ 20.0 * sin(32.0º)

the horizontal component (Vh) is __ 20.0 * cos(32.0º)

the time (T) to max height is __ Vv / g

a) Hmax = (-.5 g T^2) + (Vv * T) + 1.1

b) at Hmax, the ball has no vertical velocity; only horizontal (Vh)

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