Monday

March 30, 2015

March 30, 2015

Posted by **Sherry** on Thursday, September 13, 2012 at 11:53am.

(a) Find the maximum height of the ball above the ground.

(b) Calculate the speed of the ball at the highest point in the trajectory.

- Physics -
**Scott**, Thursday, September 13, 2012 at 2:02pmthe vertical component of the velocity (Vv)is __ 20.0 * sin(32.0º)

the horizontal component (Vh) is __ 20.0 * cos(32.0º)

the time (T) to max height is __ Vv / g

a) Hmax = (-.5 g T^2) + (Vv * T) + 1.1

b) at Hmax, the ball has no vertical velocity; only horizontal (Vh)

**Answer this Question**

**Related Questions**

Physics - A ball is thrown from a point 1.0 m above the ground. The initial ...

physics - A ball is thrown from a point 1.38 m above the ground. The initial ...

Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...

Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...

Physics - A ball is thrown from a point 1.38 m above the ground. The initial ...

PHYSICS - A ball is thrown from a point 1.1 m above the ground. The initial ...

PHYSICS - A ball is thrown from a point 1.1 m above the ground. The initial ...

PHYSICS - A ball is thrown from a point 1.2 m above the ground. The initial ...

Physics - A 0.2 kg baseball located at the top of a building which is 100 m ...

Physics - A tennis player hits a ball at ground level, giving it an initial ...