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Math(Please check)

posted by on .

This is the same equation as before just with different numbers.

y=yo + (vo sin Q) t - 1/2gt^2

This time the numbers are:

0 = 1.005 + (3.021 sin 30)t - 1/2(9.8)t^2

4.9t^2 - 1.5105 - 1.005 = 0
This is the part where I am stuck. Did I do this correctly? sin 30 = 0.50 X 3.021 = 1.5105 and then I would subtract this from 1.005

so then it would be 1.5105 - 1.005 = 0.5055 / 4.9 and square root it.

  • Math(Please check) - ,

    You are making a similar mistake to yesterday's error.
    Yesterday you just magically tagged a t at the end of the first term, now you are dropping the t from the second term

    your equation of
    0 = 1.005 + (3.021 sin 30)t - 1/2(9.8)t^2
    looks ok, assuming your replacement values were correct
    then
    0 = 1.005 + 1.5105t - 4.9t^2 , since sin 30° = 1/2

    4.9t^2 - 1.5105t - 1.005 = 0 , look at yours

    you will have to use the quadratic formula

    t = (1.5105 ± √(1.5105^2 - 4(4.9)(-1.005) )/9.8
    = .... you do the button-pushing

  • Math(Please check) - ,

    I think you dropped a t:

    4.9t^2 - 1.5105t - 1.005 = 0

    the coefficients are correct, so now you just have to solve the quadratic equation.

    t = 0.154 ± √0.229

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