Tuesday

November 25, 2014

November 25, 2014

Posted by **Katie** on Wednesday, September 12, 2012 at 11:49pm.

- Physics -
**drwls**, Thursday, September 13, 2012 at 9:42am(a) Height of object from cliff base

= H = 70 +12 t - (g/2) t^2

Set H = 0 and g = 9.8 m/s^2, and solve for t. Take the positive rooot.

(b) Vfinal^2 = Vinitial^2 + 2*g*70

= (144 +1372) m^2/s^2

Vfinal = 38.9 m/s

(c) (Up distance) + (Down distance)

= 2*(Up distance) + 70 m

= 2*Vo^2/(2*g)+70

= (Vo^2/g) + 70

- Physics -
**Elena**, Friday, October 12, 2012 at 2:59pmPlease see the Related Questions below.

**Answer this Question**

**Related Questions**

phy - A stone is thrown upward from the edge of a cliff overlooking the ocean. ...

Physics - A stone is thrown from the edge of a cliff into the ocean below. It is...

Physics - A stone is thrown from the edge of a cliff into the ocean below. It is...

physics - 9. A stone is thrown at an angle of 30° above the horizontal from the...

Physics - A stone is thrown straight up with an initial speed of 80 ft/s. How ...

physics - A stone is thrown vertically upward with a speed of 14.0 m/s from the ...

Physics - A student stands at the edge of a cliff and throws a stone ...

physics - A stone is thrown horizontally at a speed of 4.8 m/s from the top of a...

physics - a stone is thrown vertically upward with a speed of 10.5 m/s from the ...

physics - A stone is thrown vertically upward with a speed of 10.0 m/s from the ...