Posted by **Katie** on Wednesday, September 12, 2012 at 11:49pm.

A stone is thrown straight upward with a speed of 12 m/s from the edge of a 70 m high cliff. How long is the stone in the air? What is the speed just before it hits the ground? What is the total distance the stone traveled?

- Physics -
**drwls**, Thursday, September 13, 2012 at 9:42am
(a) Height of object from cliff base

= H = 70 +12 t - (g/2) t^2

Set H = 0 and g = 9.8 m/s^2, and solve for t. Take the positive rooot.

(b) Vfinal^2 = Vinitial^2 + 2*g*70

= (144 +1372) m^2/s^2

Vfinal = 38.9 m/s

(c) (Up distance) + (Down distance)

= 2*(Up distance) + 70 m

= 2*Vo^2/(2*g)+70

= (Vo^2/g) + 70

- Physics -
**Elena**, Friday, October 12, 2012 at 2:59pm
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