A stone is thrown straight upward with a speed of 12 m/s from the edge of a 70 m high cliff. How long is the stone in the air? What is the speed just before it hits the ground? What is the total distance the stone traveled?
Physics - drwls, Thursday, September 13, 2012 at 9:42am
(a) Height of object from cliff base
= H = 70 +12 t - (g/2) t^2
Set H = 0 and g = 9.8 m/s^2, and solve for t. Take the positive rooot.
(b) Vfinal^2 = Vinitial^2 + 2*g*70
= (144 +1372) m^2/s^2
Vfinal = 38.9 m/s
(c) (Up distance) + (Down distance)
= 2*(Up distance) + 70 m
= (Vo^2/g) + 70
Physics - Elena, Friday, October 12, 2012 at 2:59pm
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