Posted by Katie on Wednesday, September 12, 2012 at 11:49pm.
A stone is thrown straight upward with a speed of 12 m/s from the edge of a 70 m high cliff. How long is the stone in the air? What is the speed just before it hits the ground? What is the total distance the stone traveled?

Physics  drwls, Thursday, September 13, 2012 at 9:42am
(a) Height of object from cliff base
= H = 70 +12 t  (g/2) t^2
Set H = 0 and g = 9.8 m/s^2, and solve for t. Take the positive rooot.
(b) Vfinal^2 = Vinitial^2 + 2*g*70
= (144 +1372) m^2/s^2
Vfinal = 38.9 m/s
(c) (Up distance) + (Down distance)
= 2*(Up distance) + 70 m
= 2*Vo^2/(2*g)+70
= (Vo^2/g) + 70

Physics  Elena, Friday, October 12, 2012 at 2:59pm
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