Posted by **Robert** on Wednesday, September 12, 2012 at 11:04pm.

Algebra Question: A team wins 15 of their first 20 games. If they win only half the time from now on, how many games will they have to play in order to win 60% of their total games? I have it figured out manually, but cant get it in equation form.

- Algebra -
**Reiny**, Thursday, September 13, 2012 at 8:53am
total number of games ---- x

played so far ---- 20

to be played --- x-20

(15 + (x-20)/2 )/x = 6/10

15 + x/2 - 10 = (6/10)x

times 10

150 + 5x - 100 = 6x

x = 50

So they still have to play 30 games and win 15 of those.

check:

Having won 15 so far, and still hoping to win 15 more, ....

30/50 = 6/10 = 60%

## Answer this Question

## Related Questions

- mathrmatics - a basetball team has won 50 games of 75 played.the team still have...
- Math - Two individuals, A and B, are finalist for a chess championship. They ...
- Calculus - Your high school softball team has won ten games and lost five games...
- Pre-Algebra - Your baseball team has won 6 games and lost 4 games. If the team ...
- math - A basketball team has won 50 games of 75 played. The team still has 45 ...
- algebra 2 - Define a variable and write an inequality. Then solve. A local ...
- algebra 2 - Define a variable and write an inequality. Then solve. A local ...
- math - a local summer baseball team plays 20 games each season. so far, they ...
- algebra - Define a variable and write an inequality. Then solve. A local summer ...
- Math - A baseball team wins 60% of their first 70 games. They have 40 games left...

More Related Questions