cart rolling a a speed of 10m/s comes to a stop n 2 s. what is the car's acceleration?
a = (deltaV)/t = 10/2 = 5 m/s^2
To determine the acceleration of a car, we can use the equation for acceleration:
acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 10 m/s (cart rolling at a speed of 10 m/s)
Final velocity (v) = 0 m/s (car comes to a stop)
Time (t) = 2 s (car comes to a stop in 2 seconds)
Plugging the values into the equation, we get:
Acceleration (a) = (0 m/s - 10 m/s) / 2 s
= (-10 m/s) / 2 s
= -5 m/s²
Therefore, the car's acceleration is -5 m/s², indicating that the car is decelerating (slowing down) at a rate of 5 meters per second squared.
To determine the acceleration of the cart, you can use the formula:
Acceleration (a) = (Final velocity (v) - Initial velocity (u)) / Time taken (t)
In this case, the initial velocity (u) is 10 m/s, the final velocity (v) is 0 m/s since the cart comes to a stop, and the time taken (t) is 2 seconds.
Substituting the values into the formula:
Acceleration (a) = (0 m/s - 10 m/s) / 2 s
Simplifying this equation:
Acceleration (a) = -10 m/s / 2 s
Acceleration (a) = -5 m/s²
Therefore, the cart's acceleration is -5 m/s². The negative sign indicates the direction of acceleration, which means that the cart is decelerating or slowing down.