Homework Help: Physics

Posted by Ashley on Wednesday, September 12, 2012 at 9:49pm.

A two-stage rocket is launched straight up from rest. It accelerates at 26.4 m/s/s for 3.92 seconds during the first stage. It accelerates at 12.3 m/s/s for 4.48 more seconds during the second stage. After second stage burnout the rocket comes under the influence of gravity only. Determine its height above launch point (in meters) after 21.2 seconds from launch.

Physics - Scott, Thursday, September 13, 2012 at 12:17pm
after 1st stage:
final velocity __ Vf1 = 26.4 * 3.92
final height __ Hf1 = .5 * 26.4 * 3.92^2

after 2nd stage:
final velocity __ Vf2 = (12.3 * 4.48) + Vf1
final height __ Hf2 = (.5 * 12.3 * 4.48^2) + (Vf1 * 4.48) + Hf1

free-fall time is __ 21.2 s - 3.92 s - 4.48 s , or 12.8

H = (-.5 * g * 12.8^2) + (Vf2 * 12.8) + Hf2

Answer this Question

Related Questions

physics - Rockets A and B are fired straight upward from rest. Rocket A is ...
Physics - A toy rocket is launched upwards from rest. The rocket engine will ...
physics - space rocket travelling at 20 ms-1 accelerates at 5ms-2 for 2 seconds...
Physics - A rocket is launched straight up with constant acceleration. Four ...
Physics - A rocket is launched straight up with constant acceleration. Four ...
physics - A rocket is launched straight up with constant acceleration. Four ...
physics - A rocket is launched straight up with constant acceleration. Four ...
physics - A rocket is launched straight up with a constant acceleration. Three ...
Physics - A rocket is launched straight up with constant acceleration. Four ...
physics - A rocket is launched straight up with constant acceleration. Four ...

For Further Reading

First Name:
School Subject:
Answer: