Posted by **raj** on Wednesday, September 12, 2012 at 5:16pm.

to find the depth of the water surface in a well, a person drops a stone from the top of the well and simultaneously starts a stopwatch. The watch is stopped when the splash is heard, giving a reading of 3.65 s. The speed of sound is 340 m/s. Find the depth of the water surface below the top of the well. Take the person's reaction time for stoppping the watch to be 0.250 s.

- physics -
**Scott**, Wednesday, September 12, 2012 at 7:20pm
stone time (T) plus splash time (t) equals watch time minus reaction time

T + t = 3.65 - .25 __ t = 3.4 - T

d = .5 * g * T^2 __ g = 9.8 m/s^2

also, d = 340 * t __ d = 340(3.4 - T)

4.9 T^2 = 1156 - 340 T

4.9 T^2 + 340 T - 1156 = 0

use quadratic formula to find T, then plug in to find the depth

- physics -
**Anthony**, Monday, September 16, 2013 at 3:14pm
3.57

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