A truck covers 40.0 m in 9.40 s while smoothly slowing down to final speed 2.35 m/s. Find its accelerations
average velocity is __ 40.0 m / 9.40 s
or __ 4.26
average velocity is __ 40.0 m / 9.40 s
average equals initial plus final, divided by two
40.0 / 9.40 = (i + 2.35) / 2 __ i = 6.16
acceleration equals final minus initial, divided by time
a = (2.35 - 6.160 / 9.40
a) –4.50 m/s2
b) 4.06 m/s2
c) –4.06 m/s2
d) 4.50 m/s2
To find the acceleration, we need to use the formula:
acceleration = (final velocity - initial velocity) / time
First, let's identify the given values:
Initial velocity (u) = 0 m/s (since the truck starts from rest)
Final velocity (v) = 2.35 m/s
Time (t) = 9.40 s
Using the formula, we can calculate the acceleration:
acceleration = (2.35 m/s - 0 m/s) / 9.40 s
acceleration = 2.35 m/s / 9.40 s
To find the numerical value of the acceleration, divide 2.35 by 9.40:
acceleration = 0.25 m/s²
Therefore, the acceleration of the truck is 0.25 m/s².