I just need to know how to use the perimeter formula to work this out (dont give answer)

A rectangular certicate 8 in. by 10 in. will have a frame 1 1/2 in. wide surrounding it. What is the perimeter of the outside edge of the frame?

P = 2L + 2W

8 + 3 = 11

10 + 3 = 13

The outside of the frame is 11 by 13.

I don't like the way the problem is stated. A 1-1/2" wide frame can never go around a certificate that is 8 x 10". Ms Sue has interpreted the problem the only way it makes sense. I think the problem should have said that a frame was placed around the certificate with a space of 1-1/2". (To make it even clearer it could have added, on each side as well as top and bottom of the certificate.)

Thanks! :)

A 167

p23

To find the perimeter of the outside edge of the frame, you'll need to use the perimeter formula for a rectangle. The formula for finding the perimeter of a rectangle is:

Perimeter = 2(length + width)

In this case, the length of the frame is the length of the original certificate plus twice the width of the frame. The width of the frame is the width of the original certificate plus twice the width of the frame.

So, to calculate the perimeter of the outside edge of the frame, follow these steps:

1. Add twice the width of the frame to the length of the original certificate.
2. Add twice the width of the frame to the width of the original certificate.
3. Multiply the sum of the new length and new width by 2 to get the perimeter.

Do nots forget to convert the mixed number 1 1/2 to the improper fraction format, which is 3/2.