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A brick is thrown upward from the top of a building at an angle of 25° to the horizontal and with an initial speed of 17 m/s. If the brick is in flight for 3.3 s, how tall is the building?

  • Physics -

    the height of a freely falling object is: H = .5g*t^2 + Vo*t + Ho

    Vo is the initial vertical velocity

    Ho is the initial height (height of building)

    the height is 0 when the brick hits the ground in 3.3 sec

    g is -9.8 m/s^2

    H = .5gt^2 + [17 * sin(25º)]t + Ho

    0 = -4.9(3.3^2) + [17 * sin(25º)]3.3 + Ho

    0 = -53.4m + 23.7m + Ho

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