Posted by Crown on .
A brick is thrown upward from the top of a building at an angle of 25° to the horizontal and with an initial speed of 17 m/s. If the brick is in flight for 3.3 s, how tall is the building?
the height of a freely falling object is: H = .5g*t^2 + Vo*t + Ho
Vo is the initial vertical velocity
Ho is the initial height (height of building)
the height is 0 when the brick hits the ground in 3.3 sec
g is -9.8 m/s^2
H = .5gt^2 + [17 * sin(25º)]t + Ho
0 = -4.9(3.3^2) + [17 * sin(25º)]3.3 + Ho
0 = -53.4m + 23.7m + Ho