Homework Help: physics

Posted by anna on Wednesday, September 12, 2012 at 8:32am.

Consider a battery that has Vt = 12.0 V when it is not connected to a circuit. When a
10.0- resistor is connected with the battery, the potential difference across the battery’s terminals drops to 10.9 V. What is the internal resistance of the battery?

physics - Henry, Thursday, September 13, 2012 at 4:19pm
I = V/R = 10.9/10 = 1.09 Amps.
r = V/I = (12-10.9)/1.09 = 1.0 Ohm.
physics - Anonymous, Friday, September 14, 2012 at 2:02pm
I = V/R = 10.9/10 = 1.09 Amps.
r = V/I = (12-10.9)/1.09 = 1.0 Ohm.

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