Friday

December 19, 2014

December 19, 2014

Posted by **bobby** on Wednesday, September 12, 2012 at 8:03am.

First of all it can be computed as a sum of two integrals integrate from a to b of f(x)dx + integrate from b to c of g(x)dx

What is the value of a, b, c and what are f(x) and g(x) equal to?

Alternatively this area can be computed as a single integral

integrate from alpha to beta of h(y)dy

Alpha=?, Beta=?, h(y)=?

Either way we find that the area is: ?

- math, calculus 2 -
**Steve**, Wednesday, September 12, 2012 at 11:42amthe graphs intersect at (12,4) and (21,-5)

a = ∫[-4,12] 2√(x+4) dx + ∫[12,21] 16-x+√(x+4) dx

a = ∫[-5,4] (16-y) - (y^2-4) dy

a = 243/2

- math, calculus 2 -
**bobby**, Wednesday, September 12, 2012 at 6:26pmhow did you get the -4 in your first step? i dont understand where that came from

**Answer this Question**

**Related Questions**

Calculus Area between curves - Consider the area between the graphs x+6y=8 and x...

Cal - consider the area between the graphs x+3y=1 and x+9=y^2. this area can be ...

Cal - consider the area between the graphs x+3y=1 and x+9=y^2. this area can be ...

Calculus Please Help4 - Consider the area between the graphs x+2y=9 and x+6=y^2...

MATH 2B Calculus - Consider the area between the graphs x+4y=14 and x+7=y^2. ...

Calculus - Consider the area between the graphs x+1y=12 and x+8=y2 . This area ...

CAL - consider the area between the graphs x+3y=1 and x+9=y^2. this area can be ...

Calculus - Integrals: When we solve for area under a curve, we must consider ...

math, calculus - 1. Consider the region bounded by the curves y=|x^2+x-12|, x=-5...

calculus - Consider the graphs of y = 3x + c and y^2 = 6x, where c is a real ...