Posted by **Simran kaur** on Wednesday, September 12, 2012 at 4:37am.

In a trapezium ABCD,ABperpendicular DC.if angle A=4x degree,angle B=(6x+10degree),angle C=(3x-10degree) & angle D=5x degree.find each angle of trapezium.

- Math -
**Reiny**, Wednesday, September 12, 2012 at 9:03am
The angle sum of a trapezium must be 360° , so

4x + 6x+10 + 3x-10 + 5x = 360

18x = 360

x = 20

angle A = 80°

angle B = 130°

angle C = 50°

angle D = 100°

I don't see any perpendicular sides.

Your question contains a contradiction.

- Math -
**Steve**, Wednesday, September 12, 2012 at 11:51am
I think he meant AB parallel to DC, if vertices are labeled in cyclic order

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