posted by Simran kaur on .
In a trapezium ABCD,ABperpendicular DC.if angle A=4x degree,angle B=(6x+10degree),angle C=(3x-10degree) & angle D=5x degree.find each angle of trapezium.
The angle sum of a trapezium must be 360° , so
4x + 6x+10 + 3x-10 + 5x = 360
18x = 360
x = 20
angle A = 80°
angle B = 130°
angle C = 50°
angle D = 100°
I don't see any perpendicular sides.
Your question contains a contradiction.
I think he meant AB parallel to DC, if vertices are labeled in cyclic order