Posted by Dylan on Tuesday, September 11, 2012 at 11:44pm.
If you count the dice as unique,
there are 6^3 = 216 possible outcomes
There are 42 where the sum is at most 6.
p(sum <= 6) = 42/216 = 7/36
1 1 1
1 1 2
1 1 3
1 1 4 and permutations: 24
1 2 2
1 2 3 and permutations: 12
2 2 2 and permutations: 6
If the dice are indistinguishable, then
there are 56 outcomes
there are 6 where sum <= 6
p(sum <= 6) = 6/56 = 3/28
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