Posted by CASSIE on Tuesday, September 11, 2012 at 10:18pm.
THE VALUE 2 TO THE 8TH POWER  1 IS DIVISIBLE BY THREE PRIME NUMBERS. WHAT IS THE SUM OF THE THREE PRIME NUMBERS?

MATH  Jason, Tuesday, September 11, 2012 at 10:25pm
Just start at 2 and divide 255 which is (2^8)1.
255/2 =127.5
Not divisible by 2.
255/3 = 85
We have one prime number, 3.
255/5 = 51
We have two prime numbers  3,5.
255/7 = 36.43
Not divisible by 7
255/9 = 28.33
Not divisible by 9
255/11 = 23.18
Not divisible by 11
.
.
.
255/17 = 15
We have three prime numbers  3,5,17.
So the sum of them are:
3+5+17 = 25

MATH  Steve, Wednesday, September 12, 2012 at 10:27am
or, since a^2b^2 = (ab)(a+b)
(2^81) = (161)(16+1) = (41)(4+1)(16+1) = 3*5*17
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