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April 20, 2015

April 20, 2015

Posted by **Vitaly** on Tuesday, September 11, 2012 at 9:48pm.

- physics -
**Jason**, Tuesday, September 11, 2012 at 10:08pmTo answer this question first it helps to know the first ants speed as cm/s:

16 meters/second * 1000cm/m = 1600 cm/s

Which means that the first ant will reach the end of the counter in .034 seconds. The second ant is traveling at 3.99999 cm/s which means it will reach the counter in 13.5 s. So:

13.5-0.034 = 13.466s

The second ant is 13.466 s behind the first ant. Thus:

3.99999 cm/s * 13.466 s = 53.86 cm

The second ant is 53.86 cm behind the first ant when the first ant crosses the finish line.

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