Posted by Vitaly on Tuesday, September 11, 2012 at 9:48pm.
To answer this question first it helps to know the first ants speed as cm/s:
16 meters/second * 1000cm/m = 1600 cm/s
Which means that the first ant will reach the end of the counter in .034 seconds. The second ant is traveling at 3.99999 cm/s which means it will reach the counter in 13.5 s. So:
13.5-0.034 = 13.466s
The second ant is 13.466 s behind the first ant. Thus:
3.99999 cm/s * 13.466 s = 53.86 cm
The second ant is 53.86 cm behind the first ant when the first ant crosses the finish line.
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