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September 17, 2014

September 17, 2014

Posted by **shawni** on Tuesday, September 11, 2012 at 9:28pm.

- physics -
**drwls**, Tuesday, September 11, 2012 at 9:41pmV^2/2 increases by g*H m2/s^2, the potential energy loss.

The time in the air is the sum of the times spent going up and down.

The time going up is t1 = 7.79 m/s/g

The time spent coming down is given by

Vyo*t2 -(g/2)*t2^2 = -14.3 meters

Solve for t2

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