If the potential difference between a cloud and the ground is about 17 , how much charge is transferred in a lightning bolt that releases 1.2 of energy?
To find the amount of charge transferred in a lightning bolt, we need to use the relationship between energy, charge, and potential difference.
1. First, we need to understand that energy is given in joules (J) and potential difference is given in volts (V).
2. The formula relating energy (E), charge (Q), and potential difference (V) is:
E = Q * V
3. We know the energy released during the lightning bolt is 1.2 J. We also know that the potential difference between the cloud and the ground is 17 V.
4. Rearranging the formula, we can solve for the charge (Q):
Q = E / V
5. Substituting the given values into the equation, we get:
Q = 1.2 J / 17 V
6. Calculating the value:
Q ≈ 0.07 coulombs (C)
Therefore, approximately 0.07 coulombs of charge is transferred in the lightning bolt.