Tuesday

January 17, 2017
Posted by **AK** on Tuesday, September 11, 2012 at 3:35pm.

a)3

b)x^0

My answer for a) was: 1

My answer for b) was: 1

BUT

at the back of the book, the answer for a) was 0. The answer for b) was also 0.

I just don't understand why I'm wrong.

- maths, algebra -
**Steve**, Tuesday, September 11, 2012 at 4:10pmall constants have a degree of 0.

x^0 = 1

20 = 20*x^0

-10 = -10*x^0

x^0 obviously has degree 0. How did you think it was 1? The power is the degree.

x^1 (or, just x) has degree 1 - maths, algebra -
**AK**, Tuesday, September 11, 2012 at 4:37pmwell,now that i know that all constants have a degree of zero, i understand.

It's just that, i thought that numbers and variables that have no index are to the power 1; since x^1=x, I thought it would be okay to apply this rule on constants as well.

In a), I thought the degree of 3 was 1 according to the rule: x^1=x (like: 3^1=3, I just thought the index wasn't written)

and in b), I thought that since x^0=1, i had to state the degree of the 1.

And i thought the degree of 1 was 1 until you told me that all constants have a degree of zero (which is something i only just found out about and don't entirely understand [to be honest]). - maths, algebra -
**Steve**, Tuesday, September 11, 2012 at 4:44pmcool. Now it's something you don't have to worry about any more. Sometimes you have to pound these concepts in with a hammer. I know; my head still hurts.

- maths, algebra -
**Steve**, Tuesday, September 11, 2012 at 4:47pmthe reason why x^0 is 1, can be easily seen, if you have worked with exponents yet:

x^5 = x*x*x*x*x

x^2 = x*x

x^/x^2 = (x*x*x*x*x)/(x*x) = x*x*x = x63 = x^(5-2)

That is, when you divide powers, you subtract exponents.

So, x^5 / x^5 = 1, but

it is also x^(5-5) = x^0 - maths, algebra -
**Steve**, Tuesday, September 11, 2012 at 4:47pmsorry about the typos:

x^5/x^2 = (x*x*x*x*x)/(x*x) = x*x*x = x^3 = x^(5-2) - maths, algebra -
**max**, Tuesday, September 11, 2012 at 8:09pmcan you show me the work for my homework

- maths, algebra -
**AK**, Wednesday, September 12, 2012 at 4:14pmso 3 has a power of zero, correct?