A man with a mass of 100 kg slides down a vertical pole with an acceleration of 8 m/s2. What is the frictional force acting on the man?
Science - Steve, Tuesday, September 11, 2012 at 3:25pm
since g = -9.8m/s^2, there's a positive acceleration of 1.8m/s^2
F = ma = 100*1.8 = 180N