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April 21, 2014

Homework Help: DrBob222 : need help with the problem

Posted by ron on Tuesday, September 11, 2012 at 12:55am.

An unknown compound, X, is though to have a carboxyl group with a pKa of 2.0 and another ionizable group with a pKa between 5 and 8. When 75 mL of 0.1M NaOH is added to 100 mL of a 0.1M solution of X at pH 2.0, the pH increases to 6.72. Calculate the pKa of the second ionizable group of X.
This is what i got so far 0.0075 mol Naoh is added
there is 0.01 moles of solution X , but because of the relationship pH=pKa there is 0.005 moles of carboxylic acid left? That's all i have so far. please help.

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