Finite, Math, Probability
posted by Emily on .
Assume that there are 17 board
members: 9 females, and 8 males including Carl. There are 4 tasks to be assigned.
What is the probability that at least one female and Carl are assigned tasks?

number of task assignments without restrictions = C(17,4) = 2380
Carl  C
Female F
Male M
cases:
CFMM  1*C(9,1)*C(7,2) = 189
CFFM 1*C(9,2)*C(7,1) = 252
CFFF 1*C(9,3)*C(7,0) = 84
total cases with Carl and at least one female = 525
prob of the event as stated = 525/2380 = 15/68