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August 28, 2014

August 28, 2014

Posted by **Emily** on Monday, September 10, 2012 at 7:50pm.

members: 9 females, and 8 males including Carl. There are 4 tasks to be assigned.

What is the probability that at least one female and Carl are assigned tasks?

- Finite, Math, Probability -
**Reiny**, Monday, September 10, 2012 at 8:49pmnumber of task assignments without restrictions = C(17,4) = 2380

Carl ---- C

Female --F

Male ----M

cases:

CFMM --- 1*C(9,1)*C(7,2) = 189

CFFM ----1*C(9,2)*C(7,1) = 252

CFFF -----1*C(9,3)*C(7,0) = 84

total cases with Carl and at least one female = 525

prob of the event as stated = 525/2380 = 15/68

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