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January 30, 2015

Posted by **Quita** on Monday, September 10, 2012 at 4:50pm.

- college math -
**Steve**, Monday, September 10, 2012 at 6:08pmgiven any integers m > n,

a = m^2 - n^2

b = 2mn

c = m^2 + n^2

a,b,c form a Pythagorean triple

for (m,n) = (2,1) we get (3,4,5)

for (m,n) = (3,2) we get (5,12,13)

and so on

- college math -
**Quita**, Monday, September 10, 2012 at 6:23pmthanks

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