Posted by **Chasm** on Monday, September 10, 2012 at 1:10pm.

how many milliliters of a 0.46 M HCl solution are needed to react completely with a 6.4 g of zinc to form zinc (ii) chloride answer in mL

Help please :( I was absent and dont know where to start

- Ap chemistry -
**Steve**, Monday, September 10, 2012 at 2:48pm
start by reading your text book. I'm sure there's a section regarding moles.

Zn has a mol wt of 65.39, so 6.4g = 0.1 moles of Zn

Since the reaction is

Zn + 2HCl = ZnCl2 + H2

each mole of Zn reacts with 2 moles HCl

So, you need .2 moles HCl

.46M HCl has .46 moles/liter

So, you need .2/.46 = .434 liters, or 434ml

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