Posted by Alex on Monday, September 10, 2012 at 1:03pm.
a.
(H^+)(OH^-) = Kw -= 1E-14
b.
X = pH of 5; Y = pH of 4.
c.
pH = -log(H^+) Solve for (H^+)l.
d.
pH < 7 = acid
pH = 7 = neutral
pH > 7 = basic
e.
See b and d.
f.
pH + pOH = pKw = 14; then
pOH = -log(OH^-)
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