Homework Help: Physics

Posted by Andre' on Monday, September 10, 2012 at 12:59pm.

An object moves with constant acceleration 4.95 m/s2 and over a time interval reaches a final velocity of 13.2 m/s.
(a) If its initial velocity is 6.6 m/s, what is its displacement during the time interval?

Physics - Steve, Monday, September 10, 2012 at 2:33pm
v = at
13.2 = 4.95t
t = 8/3

s = vt + 1/2 at^2
s = 6.6*8/3 + 1/2 * 4.95 * (8/3)^2
s = 35.2
Physics - Willow Newman, Thursday, September 13, 2012 at 5:09pm
a) 13.2
13.2^2=6.6^2+2(4.95)(ΔX)
174.24= 43.56+9.9ΔX
130.68=9.9ΔX
ΔX=13.2

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