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March 29, 2017

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An object moves with constant acceleration 4.95 m/s2 and over a time interval reaches a final velocity of 13.2 m/s.
(a) If its initial velocity is 6.6 m/s, what is its displacement during the time interval?

  • Physics - ,

    v = at
    13.2 = 4.95t
    t = 8/3

    s = vt + 1/2 at^2
    s = 6.6*8/3 + 1/2 * 4.95 * (8/3)^2
    s = 35.2

  • Physics - ,

    a) 13.2
    13.2^2=6.6^2+2(4.95)(ΔX)
    174.24= 43.56+9.9ΔX
    130.68=9.9ΔX
    ΔX=13.2

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