Posted by Trey on Monday, September 10, 2012 at 8:33am.
Use the Henderson-Hasselbalch equation.
pH = pKa + log(B/A)
5.00 = 4.76 + log(100.82)/x
Solve for x = mols acetic acid needed.
Then calculate mL of the 17.3 M acetic acid needed to produce that many mols for 1 L.
Note:I'm a little confused by the problem. I suppose one could ADD 17.3M acetic acid in a titration mode until the pH was 5.00 but I'm having a hard time understanding how we can think acetate + acetic acid ==> acetic acid. I think this is a decidedly different problem than adding acid to acetate to form acetic acid; i.e.,
Ac^- + H^+ ==> HAc.
Related Questions
Chemistry - How many milliliters of glacial acetic acid (17.3 M) would you need...
Desperate chemistry - How many milliliters of glacial acetic acid (17.3 M) ...
Chemistry really desperate - How many milliliters of glacial acetic acid (17.3 ...
Chemistry - Pure acetic acid, known as glacial acetic acid, is a liquid with a ...
Chemistry - If 20ml of glacial acetic acid (pure HC2H3O2) is diluted to 1.5L ...
chemistry - A student found that there are 115 drops of glacial acetic acid in 2...
Chem - Please tell me if these are right! 1.How many milliliters of 0.215 M NaOH...
chemistry - If 15.0 mL of glacial acetic acid (pure HC2H3O2) is diluted to 1.50 ...
Chemistry - How many milliliters of glacial acetic acid are needed to prepare 2....
CHEMISTY HELP!!! - A professor found that there are 109 drops of glacial acetic...
For Further Reading
