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November 26, 2014

November 26, 2014

Posted by **G** on Sunday, September 9, 2012 at 9:08pm.

- Precalculas -
**Steve**, Monday, September 10, 2012 at 5:33amassume they have the same first term.

Then 29(d2-d1) = 300

29 does not divide 300, but it does divide 290

So, in order for s2=s1+300, a2-a1=10

one solution would be

a1=0 d1=1

a2=10 d2=11

0+29=29

10+29*11 = 329

a1+29d1 + 300 = (a1+10) + 29(d1+10)

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