posted by G on .
The sum of the first 30 terms of one arithmetic sequence is 300 more than the sum of the first 30 terms of another arithmetic sequence. what could the sequences be?
assume they have the same first term.
Then 29(d2-d1) = 300
29 does not divide 300, but it does divide 290
So, in order for s2=s1+300, a2-a1=10
one solution would be
10+29*11 = 329
a1+29d1 + 300 = (a1+10) + 29(d1+10)