Posted by G on Sunday, September 9, 2012 at 9:08pm.
assume they have the same first term.
Then 29(d2-d1) = 300
29 does not divide 300, but it does divide 290
So, in order for s2=s1+300, a2-a1=10
one solution would be
a1=0 d1=1
a2=10 d2=11
0+29=29
10+29*11 = 329
a1+29d1 + 300 = (a1+10) + 29(d1+10)
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