a man cashed a check for $63. the bank teller gave him six bills, but no one- dollar bills and no change. what did she give him?
$50, $5, $5, $1, $1, $1
I don't knpw
1-$50.00....1-$5.00....4-$2.00
To solve this problem, we can use a simple approach of deduction to find out what bills the bank teller gave to the man.
We know that the man cashed a check for $63, and the bank teller gave him six bills, with no one-dollar bills or change. This means that the six bills must add up to exactly $63.
Let's start by figuring out the possible combinations of bills that could add up to $63. Since no one-dollar bills were given, the possible bill denominations are $5, $10, $20, $50, and $100.
1. If the bank teller gave the man six $10 bills, the total would be 6 * $10 = $60, which is less than $63.
2. If the bank teller gave the man five $10 bills and one $20 bill, the total would be 5 * $10 + $20 = $70, which is more than $63.
3. If the bank teller gave the man three $10 bills and three $20 bills, the total would be 3 * $10 + 3 * $20 = $90, which is more than $63.
4. If the bank teller gave the man two $10 bills and four $20 bills, the total would be 2 * $10 + 4 * $20 = $100, which is more than $63.
5. If the bank teller gave the man one $10 bill and five $20 bills, the total would be 1 * $10 + 5 * $20 = $110, which is more than $63.
6. Finally, if the bank teller gave the man six $20 bills, the total would be 6 * $20 = $120, which is more than $63.
Based on these combinations, we can see that none of the possibilities add up to exactly $63. Therefore, there is no valid combination of bills that the bank teller could have given the man.